A gas can be taken from state A to state B vi | vedclass

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(D) According to the first law of thermodynamics, $\Delta U = q + w$.For path $ACB$:Heat flow into the system, $q_{ACB} = 60 	ext{ J}$.Work done by t

Vedclass · Accepted Answer

$40$

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(D) According to the first law of thermodynamics, $\Delta U = q + w$.For path $ACB$:Heat flow into the system, $q_{ACB} = 60 	ext{ J}$.Work done by the system, $w_{ACB} = -30 	ext{ J}$ (since work is done by the system).Change in internal energy, $\Delta U = q_{ACB} + w_{ACB} = 60 	ext{ J} - 30 	ext{ J} = 30 	ext{ J}$.Since internal energy $\Delta U$ is a state function, it remains the same for any path between $A$ and $B$.Therefore, for path $ADB$, $\Delta U = 30 	ext{ J}$.Given for path $ADB$, work done by the system, $w_{ADB} = -10 	ext{ J}$.Using $\Delta U = q_{ADB} + w_{ADB}$:$30 	ext{ J} = q_{ADB} - 10 	ext{ J}$.$q_{ADB} = 30 	ext{ J} + 10 	ext{ J} = 40 	ext{ J}$.

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