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(B) $1$. Meiosis is a reductional division where the chromosome number is halved.$2$. In meiosis-$I$, the homologous chromosomes separate, resulting i

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$4$ chromosomes

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(B) $1$. Meiosis is a reductional division where the chromosome number is halved.$2$. In meiosis-$I$, the homologous chromosomes separate, resulting in two daughter cells, each containing half the number of chromosomes of the parent cell.$3$. The parent cell is diploid $(2n = 8)$.$4$. After meiosis-$I$, each daughter cell will have $n = 8 / 2 = 4$ chromosomes.$5$. Therefore, the number of chromosomes in each daughter cell at the end of meiosis-$I$ is $4$.

$A$ diploid cell which has $8$ chromosomes undergoes meiosis and produces $4$ daughter cells. What is the number of chromosomes present in each daughter cell formed at the end of meiosis-$I$?

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