int {e^{log (sin x)}} , dx = | vedclass

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Question

(A) We know that $e^{\log(f(x))} = f(x)$.Therefore,the given integral becomes $\int {e^{\log (\sin x)}} \, dx = \int \sin x \, dx$.The integral of $\s

Vedclass · Accepted Answer

$-\cos x + c$

Vedclass · Answer

(A) We know that $e^{\log(f(x))} = f(x)$.Therefore,the given integral becomes $\int {e^{\log (\sin x)}} \, dx = \int \sin x \, dx$.The integral of $\sin x$ with respect to $x$ is $-\cos x + c$.Thus,$\int \sin x \, dx = -\cos x + c$.

$\int {e^{\log (\sin x)}} \, dx = $

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