$Ge(II)$ compounds are strong reducing agents,whereas $Pb(IV)$ compounds are strong oxidizing agents. This is due to:

  • A
    $Pb$ is more electropositive than $Ge$.
  • B
    The ionization potential of $Pb$ is lower than that of $Ge$.
  • C
    The ionic radii of $Pb^{2+}$ and $Pb^{4+}$ are larger than those of $Ge^{2+}$ and $Ge^{4+}$.
  • D
    The more pronounced inert pair effect in $Pb$ compared to $Ge$.

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