What is the oxidation state of sulfur in cycl | vedclass

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(D) In cyclic sulfur trioxide $(S_3O_9)$,the structure consists of a ring where each sulfur atom is bonded to two bridging oxygen atoms and two termin

Vedclass · Accepted Answer

$+6$

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(D) In cyclic sulfur trioxide $(S_3O_9)$,the structure consists of a ring where each sulfur atom is bonded to two bridging oxygen atoms and two terminal oxygen atoms (double bonded).Each sulfur atom is in the $+6$ oxidation state because it is bonded to three oxygen atoms via double bonds (or equivalent resonance structures) and is part of the $S-O-S$ linkage.Specifically,for each $S$ atom: $x + 3(-2) = 0$,leading to $x = +6$.

What is the oxidation state of sulfur in cyclic sulfur trioxide $(S_3O_9)$?

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