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(D) Color blindness is an $X$-linked recessive trait. Let $X^C$ be the allele for color blindness and $X$ be the normal allele. The man is normal-sigh

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(D) Color blindness is an $X$-linked recessive trait. Let $X^C$ be the allele for color blindness and $X$ be the normal allele. The man is normal-sighted, so his genotype is $XY$. Since his father was color-blind, it does not affect his genotype as he inherits his $Y$ chromosome from his father and $X$ from his mother. The woman's father was color-blind $(X^CY)$, so she must be a carrier $(XX^C)$ because she inherited the $X^C$ chromosome from her father. Cross: $XY$ (man) $	imes$ $XX^C$ (woman). Possible genotypes of offspring: $XX$, $XX^C$, $XY$, $X^CY$. The female offspring can be $XX$ (normal) or $XX^C$ (carrier). Neither of the female genotypes results in color blindness $(X^CX^C)$. Therefore, the probability of the daughter being color-blind is $0\%$.

$A$ normal-sighted man, whose father was color-blind, marries a woman whose father was also color-blind. They have their first child as a daughter. What is the probability that this child will be color-blind (in $\%$)?

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