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Question

(A) In a trihybrid cross involving the genotype $AaBbCc 	imes AaBbCc$,the inheritance of each gene pair follows Mendel's Law of Independent Assortmen

Vedclass · Accepted Answer

$1/64$

Vedclass · Answer

(A) In a trihybrid cross involving the genotype $AaBbCc 	imes AaBbCc$,the inheritance of each gene pair follows Mendel's Law of Independent Assortment.We can calculate the probability of the genotype $aabbcc$ by considering each gene pair independently:$1$. For the $Aa 	imes Aa$ cross,the probability of obtaining the $aa$ genotype is $1/4$.$2$. For the $Bb 	imes Bb$ cross,the probability of obtaining the $bb$ genotype is $1/4$.$3$. For the $Cc 	imes Cc$ cross,the probability of obtaining the $cc$ genotype is $1/4$.Since these events are independent,the probability of the combined genotype $aabbcc$ is the product of the individual probabilities:$P(aabbcc) = P(aa) 	imes P(bb) 	imes P(cc) = 1/4 	imes 1/4 	imes 1/4 = 1/64$.

If a trihybrid cross is performed between two plants with the genotype $AaBbCc$,what proportion of the offspring will have the genotype $aabbcc$?

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