PQRS is a square loop made of a uniform condu | vedclass

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(B) The square loop is divided into two parallel paths between $P$ and $S$: one path is the segment $PS$ directly,and the other path is $P-Q-R-S$. Sin

Vedclass · Accepted Answer

Zero at the centre of loop

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(B) The square loop is divided into two parallel paths between $P$ and $S$: one path is the segment $PS$ directly,and the other path is $P-Q-R-S$. Since the wire is uniform,the current divides inversely proportional to the resistance of the paths. According to the Biot-Savart Law,the magnetic field produced by a straight current-carrying wire at a point on its axis is zero. For the segments $PQ$,$QR$,and $RS$,the magnetic field at the center of the square can be calculated. Due to the symmetry of the current distribution and the directions of the currents in the segments,the magnetic field produced by the segment $PQ$ is cancelled by the field produced by the segment $RS$. The segment $QR$ also produces a field that is cancelled by the combined effect of the other segments or is zero at the center due to the specific geometry. Specifically,the magnetic field at the center due to any segment of a current-carrying loop where the current enters and leaves at symmetric points is zero because the contributions from different parts of the loop cancel each other out. Therefore,the net magnetic field at the center of the loop is zero.

$PQRS$ is a square loop made of a uniform conducting wire. The current enters the loop at $P$ and leaves at $S$. Then the magnetic field will be

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