The number of atoms in 558.5 g of Fe is equa | vedclass

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(B) Number of moles of $Fe = \frac{	ext{Given mass}}{	ext{Atomic mass}} = \frac{558.5}{55.85} = 10 \ mol$. Number of atoms in $10 \ mol$ of $Fe = 10

Vedclass · Accepted Answer

Twice the number of atoms in $60 \ g$ of $Carbon$

Vedclass · Answer

(B) Number of moles of $Fe = \frac{	ext{Given mass}}{	ext{Atomic mass}} = \frac{558.5}{55.85} = 10 \ mol$. Number of atoms in $10 \ mol$ of $Fe = 10 	imes N_A$. Now,check option $B$: $60 \ g$ of $C$ contains $\frac{60}{12} = 5 \ mol$ of $C$. Twice the number of atoms in $60 \ g$ of $C = 2 	imes (5 	imes N_A) = 10 	imes N_A$. Since both values are equal,option $B$ is correct.

The number of atoms in $558.5 \ g$ of $Fe$ is equal to: [Atomic mass of $Fe = 55.85 \ g/mol$]

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