When 1.0 g of a metal nitrate is converted i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the equivalent weight of the metal be $E$. The equivalent weight of the nitrate ion $(NO_3^-)$ is $62/1 = 62$. The equivalent weight of the su

Vedclass · Accepted Answer

$38$

Vedclass · Answer

(D) Let the equivalent weight of the metal be $E$. The equivalent weight of the nitrate ion $(NO_3^-)$ is $62/1 = 62$. The equivalent weight of the sulfate ion $(SO_4^{2-})$ is $96/2 = 48$. According to the law of equivalence,the number of equivalents of metal nitrate equals the number of equivalents of metal sulfate. $\frac{	ext{Mass of metal nitrate}}{	ext{Equivalent weight of metal nitrate}} = \frac{	ext{Mass of metal sulfate}}{	ext{Equivalent weight of metal sulfate}}$ $\frac{1.0}{E + 62} = \frac{0.86}{E + 48}$ $1.0(E + 48) = 0.86(E + 62)$ $E + 48 = 0.86E + 53.32$ $E - 0.86E = 53.32 - 48$ $0.14E = 5.32$ $E = \frac{5.32}{0.14} = 38$ Thus,the equivalent weight of the metal is $38$.

List-$I$ (Substance)	List-$II$ (Equivalent weight)
$A. Na_2CO_3$	$I. M/5$
$B. KMnO_4 / H^+$	$II. M/3$
$C. K_2Cr_2O_7 / H^+$	$III. M/2$
$D. KMnO_4 / H_2O$	$IV. M/6$

When $1.0 \ g$ of a metal nitrate is converted into $0.86 \ g$ of metal sulfate,what is the equivalent weight of the metal?

Similar Questions

One gram of hydrogen is found to combine with $80 \ g$ of bromine. One gram of calcium (valency $= 2$) combines with $4 \ g$ of bromine. The equivalent weight of calcium is:

If $V \ mL$ of the vapours of a substance at $NTP$ weigh $W \ g$,find the molecular weight of the substance.

If an element with a mass of $13.8 \, g$ contains $4.6 \times 10^{22}$ atoms,then the atomic mass of the element will be ..............

Oxygen contains $90\%$ of $^{16}O$ and $10\%$ of $^{18}O$. Its atomic mass is

Match the following substances in List-$I$ with their equivalent weights in List-$II$ ($M$ = Formula weight):

List-$I$ (Substance) List-$II$ (Equivalent weight)

$A. Na_2CO_3$ $I. M/5$

$B. KMnO_4 / H^+$ $II. M/3$

$C. K_2Cr_2O_7 / H^+$ $III. M/2$

$D. KMnO_4 / H_2O$ $IV. M/6$

Vedclass Test Series

Exam Paper Generator

Online Exam Module