The weight of 1 L of a hydrocarbon is more t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Avogadro's Law,at the same temperature and pressure,equal volumes of gases contain an equal number of moles. Since the volume is the

Vedclass · Accepted Answer

$C_3H_8$

Vedclass · Answer

(A) According to Avogadro's Law,at the same temperature and pressure,equal volumes of gases contain an equal number of moles. Since the volume is the same $(1 \ L)$,the weight of the gas is directly proportional to its molar mass. Given that the weight of the hydrocarbon is greater than the weight of $CO_2$,the molar mass of the hydrocarbon must be greater than the molar mass of $CO_2$. Molar mass of $CO_2 = 12 + (2 	imes 16) = 44 \ g/mol$. Now,calculate the molar masses of the options: $A) C_3H_8 = (3 	imes 12) + (8 	imes 1) = 44 \ g/mol$ $B) C_2H_6 = (2 	imes 12) + (6 	imes 1) = 30 \ g/mol$ $C) C_2H_4 = (2 	imes 12) + (4 	imes 1) = 28 \ g/mol$ $D) C_3H_6 = (3 	imes 12) + (6 	imes 1) = 42 \ g/mol$ Since the question implies the weight is greater than $CO_2$ $(44 \ g/mol)$,there appears to be a discrepancy in the provided options as none exceed $44 \ g/mol$. However,if the question meant 'equal to or greater',$C_3H_8$ is the closest match.

The weight of $1 \ L$ of a hydrocarbon is more than that of $1 \ L$ of $CO_2$ at the same temperature and pressure. What is the molecular formula of the hydrocarbon?

Similar Questions

$A$ gas mixture contains $25 \%$ He and $75 \% CH_4$ by volume at a given temperature and pressure. The percentage by mass of methane in the mixture is approximately . . . . . . (in $\%$)

Number of moles of oxygen gas evolved by electrolysis of $180 \ g$ of water?

Equal masses of methane $(CH_4)$ and oxygen $(O_2)$ are mixed in an empty container at $25\,^oC$. The fraction of the total pressure exerted by oxygen is:

$A$ gaseous mixture contains $CH_4$ and $C_2H_6$ in equimolecular proportion. The weight of $2.24 \ L$ of this mixture at $S.T.P.$ is :- .............. $g$

If $10$ volumes of dihydrogen gas react with $5$ volumes of dioxygen gas, how many volumes of water vapour would be produced?

Vedclass Test Series

Exam Paper Generator

Online Exam Module