If 10^{21} molecules are removed from 200 , m | vedclass

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Question

(A) Initial mass of $CO_2 = 200 \, mg = 0.2 \, g$. Molar mass of $CO_2 = 44 \, g/mol$. Initial number of moles = $\frac{0.2}{44} \approx 4.545 	imes

Vedclass · Accepted Answer

$2.85 	imes 10^{-3}$

Vedclass · Answer

(A) Initial mass of $CO_2 = 200 \, mg = 0.2 \, g$. Molar mass of $CO_2 = 44 \, g/mol$. Initial number of moles = $\frac{0.2}{44} \approx 4.545 	imes 10^{-3} \, mol$. Initial number of molecules = $4.545 	imes 10^{-3} 	imes 6.022 	imes 10^{23} \approx 2.737 	imes 10^{21}$ molecules. Number of molecules removed = $10^{21}$. Remaining molecules = $2.737 	imes 10^{21} - 1.0 	imes 10^{21} = 1.737 	imes 10^{21}$ molecules. Remaining moles = $\frac{1.737 	imes 10^{21}}{6.022 	imes 10^{23}} \approx 2.88 	imes 10^{-3} \, mol$.

If $10^{21}$ molecules are removed from $200 \, mg$ of $CO_2$,then the number of moles of $CO_2$ left is .....

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