How many moles of magnesium phosphate Mg_3(PO | vedclass

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(C) $1$ mole of $Mg_3(PO_4)_2$ contains $8$ moles of oxygen atoms.To find the moles of $Mg_3(PO_4)_2$ that contain $0.25$ moles of oxygen atoms,we use

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$0.03125$

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(C) $1$ mole of $Mg_3(PO_4)_2$ contains $8$ moles of oxygen atoms.To find the moles of $Mg_3(PO_4)_2$ that contain $0.25$ moles of oxygen atoms,we use the ratio:$	ext{Moles of } Mg_3(PO_4)_2 = \frac{	ext{Given moles of oxygen atoms}}{	ext{Moles of oxygen atoms in } 1 	ext{ mole of } Mg_3(PO_4)_2}$$	ext{Moles of } Mg_3(PO_4)_2 = \frac{0.25}{8} = 0.03125 	ext{ moles}$.

How many moles of magnesium phosphate $Mg_3(PO_4)_2$ contain $0.25$ moles of oxygen atoms?

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