When $32.25 \ g$ of ethyl chloride undergoes dehydrohalogenation,it yields $50\%$ of the theoretical alkene product. What is the mass of the product obtained in $g$? (Atomic mass: $Cl = 35.5, C = 12, H = 1$)

Match the reactions in Column-$A$ with the products in Column-$B$ and select the correct option:

Column-$A$	Column-$B$
$(1)$ $CH_3-CH_2-Cl + KOH_{(aq)} \rightarrow$	$(A)$ $1,2-\text{dichloroethane}$
$(2)$ $CH_3-CH_2-CH_2-CH_3 \xrightarrow{AlCl_3/HCl}$	$(B)$ $\text{Chloromethane}$
$(3)$ $CH_3-CH_2-Br + \text{alc. } KOH \rightarrow$	$(C)$ $\text{But-2-ene}$
$(4)$ $CH_2=CH_2 + Cl_2 \rightarrow$	$(D)$ $\text{Ethanol}$
	$(E)$ $\text{Chloroethane}$
	$(F)$ $\text{Ethene}$
	$(G)$ $\text{Isobutane}$

Match the reactions in List-$I$ with the major products in List-$II$:
| List-$I$ | List-$II$ (Major Product) |
| :--- | :--- |
| $(A)$ $CH_3-CHBr-CH_2Br \xrightarrow{KOH/C_2H_5OH}$ | $(I)$ $1^{\circ}$-alkyl bromide |
| $(B)$ $CH_3-CH_2-CH=CH_2 \xrightarrow{HBr, (C_6H_5CO)_2O_2, \Delta}$ | $(II)$ $2^{\circ}$-alkyl bromide |
| $(C)$ $CH_3CH_2CH_3 \xrightarrow{Br_2, h\nu}$ | $(III)$ Allyl bromide |
| $(D)$ $CH_3-CH=CH_2 \xrightarrow{NBS, \Delta}$ | $(IV)$ Alkenyl bromide |

What is the product of the following reaction?

Consider the following $E_1/S_N1$ reaction. The missing product$(s)$ is(are):

How many isomers are possible for the compound with the molecular formula $C_2BrClFI$?