How many isomers are possible for the compound with the molecular formula $C_2BrClFI$?

  • A
    $6$
  • B
    $4$
  • C
    $5$
  • D
    $3$

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Similar Questions

Match the List-$I$ with List-$II$:
List-$I$ Name reaction List-$II$ Product obtainable
$A.$ Swarts reaction $I.$ Ethyl benzene
$B.$ Sandmeyer's reaction $II.$ Ethyl iodide
$C.$ Wurtz Fittig reaction $III.$ Cyanobenzene
$D.$ Finkelstein reaction $IV.$ Ethyl fluoride

Choose the correct answer from the options given below:

How can the following conversions be carried out?
$(i)$ Propene to propan$-1-$ol
$(ii)$ Ethanol to but$-1-$yne
$(iii)$ $1-$Bromopropane to $2-$bromopropane
$(iv)$ Toluene to benzyl alcohol
$(v)$ Benzene to $4-$bromonitrobenzene
$(vi)$ Benzyl alcohol to $2-$phenylethanoic acid
$(vii)$ Ethanol to propanenitrile
$(viii)$ Aniline to chlorobenzene
$(ix)$ $2-$Chlorobutane to $3,4-$dimethylhexane
$(x)$ $2-$Methyl$-1-$propene to $2-$chloro$-2-$methylpropane
$(xi)$ Ethyl chloride to propanoic acid
$(xii)$ But$-1-$ene to $n-$butyliodide
$(xiii)$ $2-$Chloropropane to $1-$propanol
$(xiv)$ Isopropyl alcohol to iodoform
$(xv)$ Chlorobenzene to $p-$nitrophenol
$(xvi)$ $2-$Bromopropane to $1-$bromopropane
$(xvii)$ Chloroethane to butane
$(xviii)$ Benzene to diphenyl
$(xix)$ tert-Butyl bromide to isobutyl bromide
$(xx)$ Aniline to phenylisocyanide

Match the following lists:
List-$I$List-$II$
$(A)$ Benzene$1$. Phosgene
$(B)$ Ethylene$2$. Silver mirror
$(C)$ Acetaldehyde$3$. Mustard gas
$(D)$ Chloroform$4$. $(4n + 2) \pi$ electrons
$5$. Carbylamine

In the reaction shown below,the structural formula of $(A)$,$X$ and $Y$ respectively are:
$C_7H_7N_2OCl + C_2H_5OH \rightarrow \text{Anisole} + N_2 + X + Y$

Match the reactions in Column-$I$ with their mechanisms in Column-$II$.
Column-$I$ (Reaction) Column-$II$ (Mechanism)
$(A)$ $OH^- + CH_3Cl \to HOCH_3 + Cl^-$ $(1)$ $S_N2$ mechanism
$(B)$ $(CH_3)_3CBr + OH^- \to (CH_3)_3COH + Br^-$ $(2)$ $S_E2$ aromatic
$(C)$ $CH_3CH_2Br \xrightarrow[ethanol]{KOH} CH_2 = CH_2$ $(3)$ $S_N1$ mechanism
$(D)$ $C_6H_6 + Br_2 \xrightarrow{Fe} C_6H_5Br + HBr$ $(4)$ $\beta$-elimination (dehydrohalogenation)

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