The equivalent weight of potassium permangana | vedclass

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Question

(B) In an alkaline medium,$KMnO_4$ acts as an oxidizing agent and is reduced to $MnO_2$. The chemical reaction is: $2KMnO_4 + H_2O \rightarrow 2MnO_2

Vedclass · Accepted Answer

Molecular weight $/ 3$

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(B) In an alkaline medium,$KMnO_4$ acts as an oxidizing agent and is reduced to $MnO_2$. The chemical reaction is: $2KMnO_4 + H_2O ightarrow 2MnO_2 + 2KOH + 3[O]$. The change in the oxidation state of $Mn$ is from $+7$ to $+4$,so the change in oxidation number is $7 - 4 = 3$. The equivalent weight is calculated as: $	ext{Equivalent weight} = \frac{	ext{Molecular weight}}{	ext{n-factor}} = \frac{	ext{Molecular weight}}{3}$.

The equivalent weight of potassium permanganate in an alkaline medium is........

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