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(B) The reaction of $BaS_2O_3$ with dilute $HCl$ produces $SO_2$ gas (pungent smell) and elemental sulfur (yellow crystals).$BaS_2O_3 + 2HCl 	o BaCl_

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$BaS_2O_3$

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(B) The reaction of $BaS_2O_3$ with dilute $HCl$ produces $SO_2$ gas (pungent smell) and elemental sulfur (yellow crystals).$BaS_2O_3 + 2HCl 	o BaCl_2 + SO_2 \uparrow + S \downarrow + H_2O$$Ba^{2+}$ ions impart a characteristic apple-green color to the flame.$Ba^{2+}$ reacts with potassium chromate $(K_2CrO_4)$ to form a yellow precipitate of barium chromate $(BaCrO_4)$:$Ba^{2+} + K_2CrO_4 	o BaCrO_4 \downarrow + 2K^+$Thus,the salt is $BaS_2O_3$.

$A$ salt reacts with dilute $HCl$ to produce a gas with a pungent smell and yellow crystals. When tested,the salt gives a green flame. With potassium chromate,the salt gives yellow crystals. Therefore,the salt is.......

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