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(B) Sodium carbonate $(Na_2CO_3)$ is a salt of a strong base $(NaOH)$ and a weak acid $(H_2CO_3)$.When dissolved in water,it undergoes hydrolysis as f

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(B) Sodium carbonate $(Na_2CO_3)$ is a salt of a strong base $(NaOH)$ and a weak acid $(H_2CO_3)$.When dissolved in water,it undergoes hydrolysis as follows:$CO_3^{2-} + H_2O ightleftharpoons HCO_3^- + OH^-$From the stoichiometry of the reaction,$1 	ext{ mole}$ of $CO_3^{2-}$ ions produces $1 	ext{ mole}$ of $OH^-$ ions.Therefore,the hydrolysis of $1 	ext{ mole}$ of $Na_2CO_3$ produces $1 	ext{ mole}$ of hydroxide ions $(OH^-)$.

Column $I$	Column $II$
$A$. $CH_3COONa$	$i$. Almost neutral,$pH > 7$ or $< 7$
$B$. $NH_4Cl$	$ii$. Acidic,$pH < 7$
$C$. $NaNO_3$	$iii$. Alkaline,$pH > 7$
$D$. $CH_3COONH_4$	$iv$. Neutral,$pH = 7$

How many hydroxide ions are produced by the hydrolysis of one mole of sodium carbonate $(Na_2CO_3)$?

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Column $I$ Column $II$

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