The number of unpaired electrons in Ni^{2+} ( | vedclass

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Question

(B) The atomic number of $Ni$ is $28$. The electronic configuration of $Ni$ is $[Ar] 3d^8 4s^2$. When $Ni$ forms $Ni^{2+}$ ion,it loses two electrons

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) The atomic number of $Ni$ is $28$. The electronic configuration of $Ni$ is $[Ar] 3d^8 4s^2$. When $Ni$ forms $Ni^{2+}$ ion,it loses two electrons from the $4s$ orbital. The electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8 4s^0$. In the $3d^8$ subshell,the electrons are filled as follows: $3d^8$: $\uparrow\downarrow, \uparrow\downarrow, \uparrow\downarrow, \uparrow, \uparrow$. There are $2$ unpaired electrons in the $3d$ orbital. Thus,the correct option is $B$.

The number of unpaired electrons in $Ni^{2+}$ (atomic number $= 28$) is ...... .

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