The correct combination is

  • A
    $[NiCl_4]^{2-} -$ square-planar; $[Ni(CN)_4]^{2-} -$ paramagnetic
  • B
    $[Ni(CN)_4]^{2-} -$ tetrahedral; $[Ni(CO)_4] -$ paramagnetic
  • C
    $[NiCl_4]^{2-} -$ paramagnetic; $[Ni(CO)_4] -$ tetrahedral
  • D
    $[NiCl_4]^{2-} -$ diamagnetic; $[Ni(CO)_4] -$ square-planar

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Which of the following statements is $NOT$ correct regarding the complex $[Co(NH_3)_6]^{3+}$?

Which of the following pairs of compounds is planar?

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Give the correct sequence of initials $T$ or $F$ for the following statements. Use $T$ if the statement is true and $F$ if it is false.
$(I) \ Co(III)$ is stabilized in the presence of weak field ligands,while $Co(II)$ is stabilized in the presence of strong field ligands.
$(II)$ Four-coordinated complexes of $Pd(II)$ and $Pt(II)$ are diamagnetic and square planar.
$(III) \ [Ni(CN)_4]^{4-}$ ion and $[Ni(CO)_4]$ are diamagnetic tetrahedral and square planar respectively.
$(IV) \ Ni^{2+}$ ion does not form inner orbital octahedral complexes.

$K_3[CoF_6]$ is a high-spin complex. The hybridization state of $Co$ in this complex is .....................

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