An element has an outermost orbital configuration of $4s^2$. What is its atomic number?

  • A
    $29$
  • B
    $24$
  • C
    $30$
  • D
    $19$

Explore More

Similar Questions

The atomic number of an element having the valence shell electronic configuration $4s^2 4p^6$ is

The explanation for the presence of three unpaired electrons in the nitrogen atom can be given by

After filling the $4d$ orbitals,an electron will enter in:

Assertion : Spin quantum number can have two values,$+\frac{1}{2}$ and $-\frac{1}{2}$.
Reason : $+$ and $-$ signs signify the positive and negative wave functions.

The value of the azimuthal quantum number for electrons present in the $4p$ orbital is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo