The ratio of the radius of the second orbit o | vedclass

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(B) The radius of an orbit in a hydrogen-like species is given by the formula $r_n = 0.529 	imes \frac{n^2}{Z} \ \mathring{A}$.
For the second orbit

Vedclass · Accepted Answer

$4 : 3$

Vedclass · Answer

(B) The radius of an orbit in a hydrogen-like species is given by the formula $r_n = 0.529 	imes \frac{n^2}{Z} \ \mathring{A}$.
For the second orbit of hydrogen $(n=2, Z=1)$: $(r_2)_H = 0.529 	imes \frac{2^2}{1} = 0.529 	imes 4 \ \mathring{A}$.
For the third orbit of $Li^{+2}$ $(n=3, Z=3)$: $(r_3)_{Li^{+2}} = 0.529 	imes \frac{3^2}{3} = 0.529 	imes 3 \ \mathring{A}$.
The ratio is $\frac{(r_2)_H}{(r_3)_{Li^{+2}}} = \frac{0.529 	imes 4}{0.529 	imes 3} = \frac{4}{3}$.
Thus,the ratio is $4 : 3$.

The ratio of the radius of the second orbit of hydrogen to the third orbit of $Li^{+2}$ is .... ($H$ atomic number = $1, Li$ atomic number = $3$)

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