If the electronic configuration of a nitrogen atom were $1s^7$,its energy would be lower than the ground state configuration $1s^2 2s^2 2p^3$ because the electrons would be closer to the nucleus. However,the configuration $1s^7$ is not observed. Which of the following principles is violated?

  • A
    Heisenberg uncertainty principle
  • B
    Hund's rule
  • C
    Pauli exclusion principle
  • D
    Bohr's postulates of stationary orbits

Explore More

Similar Questions

The electronic configuration together with the quantum numbers of the last electron for lithium $(Li)$ is:

Find the number of unpaired electrons for copper in ground state configuration.

For $n = 5$ and $m = 2$,which of the following statements is incorrect?

An ion with a charge of $-2$ has the electronic configuration $1s^2, 2s^2, 2p^6$. Identify the ion.

Which orbitals are present in a hydrogen atom?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo