The sum of paired electrons present in l = 2 | vedclass

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(B) The $l = 2$ orbital corresponds to the $d$-subshell.$1$. For $_{26}Fe^{2+}$: Electronic configuration is $[Ar] 3d^6$. In $3d^6$,there is $1$ paire

Vedclass · Accepted Answer

$12$

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(B) The $l = 2$ orbital corresponds to the $d$-subshell.$1$. For $_{26}Fe^{2+}$: Electronic configuration is $[Ar] 3d^6$. In $3d^6$,there is $1$ paired electron set (containing $2$ electrons) and $4$ unpaired electrons. Number of paired electrons = $2$.$2$. For $_{27}Co^{2+}$: Electronic configuration is $[Ar] 3d^7$. In $3d^7$,there are $2$ paired electron sets (containing $4$ electrons) and $3$ unpaired electrons. Number of paired electrons = $4$.$3$. For $_{28}Ni^{2+}$: Electronic configuration is $[Ar] 3d^8$. In $3d^8$,there are $3$ paired electron sets (containing $6$ electrons) and $2$ unpaired electrons. Number of paired electrons = $6$.Total number of paired electrons = $2 + 4 + 6 = 12$.

The sum of paired electrons present in $l = 2$ orbitals for the species $Fe^{2+}$,$Co^{2+}$,and $Ni^{2+}$ is .......

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