A reactant undergoes 90% decomposition in 366 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a first-order reaction,the rate constant $K$ is given by: $K = \frac{2.303}{t} \log \frac{[A]_0}{[A]_t}$ Given $t = 366 	ext{ min}$ and $[A]_

Vedclass · Accepted Answer

$366 \left( \frac{\ln 2}{\ln 10} \right)$

Vedclass · Answer

(B) For a first-order reaction,the rate constant $K$ is given by: $K = \frac{2.303}{t} \log \frac{[A]_0}{[A]_t}$ Given $t = 366 	ext{ min}$ and $[A]_t = 10\% 	ext{ of } [A]_0$,so $\frac{[A]_0}{[A]_t} = \frac{100}{10} = 10$. $K = \frac{2.303}{366} \log 10 = \frac{2.303}{366}$. The half-life $t_{1/2}$ is given by: $t_{1/2} = \frac{0.693}{K} = \frac{\ln 2}{K}$. Substituting $K$: $t_{1/2} = \frac{\ln 2}{(2.303 / 366)} = \frac{366 	imes \ln 2}{2.303}$. Since $2.303 = \ln 10$,we get $t_{1/2} = 366 \left( \frac{\ln 2}{\ln 10} ight)$.

Time	$t$	$\infty$
$P_{\text{system}}$	$P_t$	$P_{\infty}$

$A$ reactant undergoes $90\%$ decomposition in $366 \text{ minutes}$. What is the half-life of this first-order reaction?

Similar Questions

$A_{(g)} \rightarrow B_{(g)} + C_{(g)}$ is a first order reaction.

Time $t$ $\infty$

$P_{\text{system}}$ $P_t$ $P_{\infty}$

The reaction was started with reactant $A$ only. Which of the following expressions is correct for the rate constant $k$?

For the first-order reaction $2N_2O_{5(g)} \rightarrow 4NO_{2(g)} + O_{2(g)}$,which of the following statements is incorrect?

What is the value of the slope when a graph is plotted of $\log \frac{[R]_0}{[R]}$ versus $t$ (time) for a first-order reaction?

The half-life of a first-order reaction is $10 \ min$. If the initial concentration is $0.08 \ mol \ L^{-1}$ and the concentration at some instant is $0.01 \ mol \ L^{-1}$,then $t =$ ........... $\min$.

Thermal decomposition of a compound is of first order. If $50\%$ of a sample of this compound is decomposed in $120 \ min$,then how long will it take $90\%$ of the compound to decompose? ........ $min.$

Vedclass Test Series

Exam Paper Generator

Online Exam Module