Reactant $(A)$ produces two products. If $Ea_2 = 2 Ea_1$,then $K_1$ and $K_2$ are related as:
$A \xrightarrow{K_1} B$,activation energy: $Ea_1$
$A \xrightarrow{K_2} C$,activation energy: $Ea_2$
$A \xrightarrow{K_1} B$,activation energy: $Ea_1$
$A \xrightarrow{K_2} C$,activation energy: $Ea_2$
- A$K_1 = 2 K_2 e^{Ea_2/RT}$
- B$K_2 = K_1 e^{Ea_1/RT}$
- C$K_2 = K_1 e^{Ea_2/RT}$
- D$K_1 = A' K_2 e^{Ea_1/RT}$
Explore More
Similar Questions
Which equation is true to calculate the energy of activation,if the rate of reaction is doubled by increasing temperature from $T_1 \ K$ to $T_2 \ K$?
How does the graph of the fraction of molecules versus kinetic energy change at different temperatures?
Medium
View SolutionActivation energy of any reaction depends on
Easy
View SolutionThe velocity constant of a reaction at $290 \ K$ was found to be $3.2 \times 10^{-3}$. At $300 \ K$ it will be
Medium
View SolutionAccording to the collision theory of reaction rates:
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo