How many liters of water must be added to 1 | vedclass

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(D) For $pH = 1$,the concentration of $H^+$ ions is $[H^+]_1 = 10^{-pH} = 10^{-1} \ M$.For $pH = 2$,the concentration of $H^+$ ions is $[H^+]_2 = 10^{

Vedclass · Accepted Answer

$9$

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(D) For $pH = 1$,the concentration of $H^+$ ions is $[H^+]_1 = 10^{-pH} = 10^{-1} \ M$.For $pH = 2$,the concentration of $H^+$ ions is $[H^+]_2 = 10^{-pH} = 10^{-2} \ M$.Using the dilution formula $M_1V_1 = M_2V_2$:$10^{-1} \ M 	imes 1 \ L = 10^{-2} \ M 	imes V_2$$V_2 = \frac{10^{-1}}{10^{-2}} = 10 \ L$.The initial volume $V_1$ is $1 \ L$,so the volume of water to be added is $V_{added} = V_2 - V_1 = 10 \ L - 1 \ L = 9 \ L$.

How many liters of water must be added to $1 \ L$ of an aqueous $HCl$ solution with $pH = 1$ to change its $pH$ to $2$?

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