Aqueous solutions of 1 M potassium acetate a | vedclass

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(B) Both $CH_3COOK$ and $HCOOK$ undergo hydrolysis in water to form their respective weak acids,$CH_3COOH$ and $HCOOH$.The degree of hydrolysis $(h)$

Vedclass · Accepted Answer

$[CH_3COOH] > [HCOOH]$

Vedclass · Answer

(B) Both $CH_3COOK$ and $HCOOK$ undergo hydrolysis in water to form their respective weak acids,$CH_3COOH$ and $HCOOH$.The degree of hydrolysis $(h)$ is given by $h = \sqrt{\frac{K_h}{C}}$.Since $K_h = \frac{K_w}{K_a}$,we have $h = \sqrt{\frac{K_w}{K_a 	imes C}}$.The concentration of the acid formed is $[Acid] = C 	imes h = \sqrt{\frac{K_w 	imes C}{K_a}}$.Since $K_a$ of $HCOOH$ $(1.8 	imes 10^{-4})$ is greater than $K_a$ of $CH_3COOH$ $(1.8 	imes 10^{-5})$,the concentration of $HCOOH$ formed will be less than the concentration of $CH_3COOH$ formed.Therefore,$[CH_3COOH] > [HCOOH]$.

Aqueous solutions of $1 \ M$ potassium acetate and $1 \ M$ potassium formate are taken in separate beakers. Which of the following relationships is correct?

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