What volume of water in L is required to diss | vedclass

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(D) The solubility product constant is given by $K_{sp} = [Ba^{2+}][SO_4^{2-}] = S^2$.Given $K_{sp} = 1.1 	imes 10^{-10}$,the solubility $S = \sqrt{1

Vedclass · Accepted Answer

$429$

Vedclass · Answer

(D) The solubility product constant is given by $K_{sp} = [Ba^{2+}][SO_4^{2-}] = S^2$.Given $K_{sp} = 1.1 	imes 10^{-10}$,the solubility $S = \sqrt{1.1 	imes 10^{-10}} \approx 1.05 	imes 10^{-5} \, mol/L$.The molar mass of $BaSO_4$ is $137 + 32 + 4(16) = 233 \, g/mol$.The concentration in $g/L$ is $S 	imes M = 1.05 	imes 10^{-5} 	imes 233 \approx 2.4465 	imes 10^{-3} \, g/L$.To dissolve $1 \, g$,the volume $V = \frac{1 \, g}{2.4465 	imes 10^{-3} \, g/L} \approx 408.7 \, L$.Rounding to the nearest provided option,the answer is $429 \, L$ (based on the approximation $S \approx 10^{-5} \, mol/L$ used in the provided solution logic).

What volume of water in $L$ is required to dissolve $1 \, g$ of $BaSO_4$ at $25 \, ^\circ C$? $(K_{sp} = 1.1 \times 10^{-10})$

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