Calculate the molar solubility of calcium hydroxide $Ca(OH)_2$ in $0.10 \ M \ NaOH$ solution. The solubility product constant $(K_{sp})$ of calcium hydroxide is $5.5 \times 10^{-6}$.

  • A
    $1.1 \times 10^{-4}$
  • B
    $5.5 \times 10^{-5}$
  • C
    $5.5 \times 10^{-4}$
  • D
    $5.5 \times 10^{-6}$

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