$A$ reversible reaction involving two reactants is at equilibrium. If the concentration of the reactants is doubled,the equilibrium constant will ......

One mole of $A_{(g)}$ is heated to $200^{\circ} C$ in a one litre closed flask,until the following equilibrium is reached:
$A_{(g)} \rightleftharpoons B_{(g)}$
The rate of forward reaction at equilibrium is $0.02 \ mol \ L^{-1} \ min^{-1}$. What is the rate (in $mol \ L^{-1} \ min^{-1}$) of the backward reaction at equilibrium?

Explain solid-liquid equilibrium by giving an example.

For the equilibrium $A \rightleftharpoons B$,the variation of the rate of the forward $(a)$ and reverse $(b)$ reaction with time is given by:

If the concentration of reactants is increased by $x$ times,the equilibrium constant $K$ will become ................

The $K_c$ for $H_{2(g)} + I_{2(g)} \rightleftharpoons 2HI_{(g)}$ is $64$. If the volume of the container is reduced to one-half of its original volume,the value of the equilibrium constant will be