Vedclass
Class 11Chemistry6-2.Equilibrium-II (Ionic Equilibrium)Solubility product
Difficult

If the solubility of salts $M_2X$,$QY_2$,and $PZ_3$ is the same $(S < 1)$,what is the relationship between their solubility products $(K_{sp})$?

  • A
    $K_{sp}(M_2X) = K_{sp}(QY_2) < K_{sp}(PZ_3)$
  • B
    $K_{sp}(M_2X) > K_{sp}(QY_2) = K_{sp}(PZ_3)$
  • C
    $K_{sp}(M_2X) = K_{sp}(QY_2) > K_{sp}(PZ_3)$
  • D
    $K_{sp}(M_2X) > K_{sp}(QY_2) > K_{sp}(PZ_3)$
Share

Explore More

Browse All

Question Bank

11

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

6-2.Equilibrium-II (Ionic Equilibrium)

Subtopic

Solubility product

Similar Questions

Which is the correct representation of the solubility product constant of $Ag_2CrO_4$?

Medium
View Solution

Solubility product is

Easy
View Solution

The $K_{sp}$ values of $Ag_2CrO_4, AgCl, AgBr,$ and $AgI$ are $1.1 \times 10^{-12}, 1.8 \times 10^{-10}, 5.0 \times 10^{-13},$ and $8.3 \times 10^{-17}$ respectively. If $AgNO_3$ solution is added to a solution containing equal moles of $NaCl, NaBr, NaI,$ and $Na_2CrO_4$,which will precipitate last?

Easy
View Solution

The solubility of silver chromate in $0.01 \, M$ $K_2CrO_4$ is $2 \times 10^{-8} \, mol \, dm^{-3}$. The solubility product of silver chromate will be

Medium
View Solution

The $K_{sp}$ of $AgI$ is $1.5 \times 10^{-16}$. Which of the following mixtures of equal volumes will result in precipitation?

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo