$A$ man of mass $50 \ kg$ carrying a load of $10 \ kg$ reaches the top of a building in $4 \ minutes$. The work done by the man is $6 \times 10^4 \ J$. If he reaches the top in $2 \ minutes$,the work done by the man will be:
- A$1.5 \times 10^4 \ J$
- B$3.3 \times 10^4 \ J$
- C$6 \times 10^4 \ J$
- D$12.1 \times 10^4 \ J$
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