A block of ice at 0^{circ}C falls from a heig | vedclass

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(A) The potential energy of the ice block at height $h$ is converted into kinetic energy,which is then converted into heat upon impact.Let $m$ be the

Vedclass · Accepted Answer

$\frac{1}{33}$

Vedclass · Answer

(A) The potential energy of the ice block at height $h$ is converted into kinetic energy,which is then converted into heat upon impact.Let $m$ be the mass of the ice block and $k$ be the fraction of ice that melts.The potential energy $PE = mgh$.The heat required to melt a fraction $k$ of the ice is $Q = k \cdot m \cdot L$.Equating the energy: $mgh = kmL$.Therefore,$k = \frac{gh}{L}$.Given $g = 10 \ m/s^{2}$,$h = 1000 \ m$,and $L = 3.36 	imes 10^{5} \ J/kg$.$k = \frac{10 	imes 1000}{3.36 	imes 10^{5}} = \frac{10000}{336000} = \frac{1}{33.6} \approx \frac{1}{33}$.

$A$ block of ice at $0^{\circ}C$ falls from a height of $1 \ km$ onto an insulating surface. If all its kinetic energy is converted into heat,what fraction of the ice will melt? (Take $g = 10 \ m/s^{2}$ and latent heat of fusion of ice $L = 3.36 \times 10^{5} \ J/kg$)

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