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(B) For proper demodulation in an $AM$ detector,the time constant $RC$ must satisfy the condition: $\frac{1}{f_c} \ll RC < \frac{1}{f_m}$,where $f_c$

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No

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(B) For proper demodulation in an $AM$ detector,the time constant $RC$ must satisfy the condition: $\frac{1}{f_c} \ll RC First,calculate the period of the carrier signal: $\frac{1}{f_c} = \frac{1}{100 	imes 10^3 \ Hz} = 10^{-5} \ s$.Next,calculate the time constant of the circuit: $RC = (10^3 \ \Omega) 	imes (10 	imes 10^{-12} \ F) = 10^{-8} \ s$.Comparing the two,we see that $RC = 10^{-8} \ s$ is much smaller than $\frac{1}{f_c} = 10^{-5} \ s$.Since the condition $\frac{1}{f_c} \ll RC$ is not satisfied,the circuit cannot effectively detect the $100 \ kHz$ carrier signal.

In a diode $AM$ detector,the output circuit has $R = 1 \ k\Omega$ and $C = 10 \ pF$. Can it detect a carrier signal of $100 \ kHz$?

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