At what temperature is the average kinetic en | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The average kinetic energy of a gas molecule is given by $K_{avg} = \frac{3}{2}kT$,where $k$ is the Boltzmann constant and $T$ is the temperature

Vedclass · Accepted Answer

$7.7 	imes 10^3 \, K$

Vedclass · Answer

(D) The average kinetic energy of a gas molecule is given by $K_{avg} = \frac{3}{2}kT$,where $k$ is the Boltzmann constant and $T$ is the temperature in Kelvin.The energy gained by an electron accelerated through a potential difference of $V = 1 \, V$ is $E = qV = 1 \, eV$.Equating the two: $\frac{3}{2}kT = 1 \, eV$.Substituting the values $e = 1.6 	imes 10^{-19} \, C$ and $k = 1.38 	imes 10^{-23} \, J/K$:$T = \frac{2 	imes 1.6 	imes 10^{-19}}{3 	imes 1.38 	imes 10^{-23}} \, K$.$T = \frac{3.2 	imes 10^{-19}}{4.14 	imes 10^{-23}} \, K \approx 0.7729 	imes 10^4 \, K = 7.7 	imes 10^3 \, K$.

At what temperature is the average kinetic energy equal to the energy gained by an electron accelerated from rest through a potential difference of $1 \, V$?

Similar Questions

The relationship between the kinetic energy per unit volume $(E)$ and the pressure $(P)$ for a given gas is .....

At $...... ^\circ C$ temperature,the mean kinetic energy of ${O_2}$ molecules will be the same as that of ${H_2}$ molecules at $-73^\circ C$.

$A$ gas is filled in a container at pressure ${P_0}$. If the mass of all molecules is halved and their $rms$ speed is doubled,what will be the new pressure?

$A$ parallel beam of particles of mass $m$ moving with velocity $v$ impinges on a wall at an angle $\theta$ to its normal. The number of particles per unit volume in the beam is $n$. If the collision of particles with the wall is elastic,then the pressure exerted by this beam on the wall is

If $10^{22}$ gas molecules,each of mass $10^{-26} \ kg$,collide with a surface (perpendicular to it) elastically per second over an area of $1 \ m^2$ with a speed of $10^4 \ m/s$,the pressure exerted by the gas molecules will be of the order of:

Vedclass Test Series

Exam Paper Generator

Online Exam Module