The kinetic energy of one mole of a gas at 30 | vedclass

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(A) The average kinetic energy of one mole of an ideal gas is given by the formula $E = \frac{3}{2} RT$.Since $R$ is the universal gas constant and th

Vedclass · Accepted Answer

$1.33$

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(A) The average kinetic energy of one mole of an ideal gas is given by the formula $E = \frac{3}{2} RT$.Since $R$ is the universal gas constant and the amount of gas (one mole) is constant,the kinetic energy $E$ is directly proportional to the absolute temperature $T$ $(E \propto T)$.Therefore,the ratio of kinetic energies at two different temperatures $T$ and $T'$ is given by $\frac{E'}{E} = \frac{T'}{T}$.Given $T = 300 \, K$ and $T' = 400 \, K$,we substitute these values into the ratio:$\frac{E'}{E} = \frac{400 \, K}{300 \, K} = \frac{4}{3} = 1.33$.

The kinetic energy of one mole of a gas at $300 \, K$ is $E$. If the kinetic energy at $400 \, K$ is $E'$,then what is the ratio $E'/E$?

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