If the nuclear forces between two protons,two neutrons,and a proton-neutron are denoted by $F_{pp}$,$F_{nn}$,and $F_{pn}$ respectively,then:

  • A
    $F_{pp} \approx F_{nn} \approx F_{pn}$
  • B
    $F_{pp} \neq F_{nn}$ and $F_{pp} = F_{nn}$
  • C
    $F_{pp} = F_{nn} = F_{pn}$
  • D
    $F_{pp} \neq F_{nn} \neq F_{pn}$

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Assertion $(A):$ Forces acting between proton-proton $(f_{pp})$, proton-neutron $(f_{pn})$ and neutron-neutron $(f_{nn})$ are such that $f_{pp} < f_{pn} = f_{nn}$.
Reason $(R):$ Electrostatic force of repulsion between two protons reduces the net nuclear force between them.

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$F_{pp}$, $F_{nn}$, and $F_{np}$ are the nuclear forces between proton-proton, neutron-neutron, and neutron-proton respectively. Then the relation between them is:

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