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(C) Energy is released in a nuclear process if the total binding energy of the products is greater than the total binding energy of the reactants. Thi

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$(i)$ and $(iv)$

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(C) Energy is released in a nuclear process if the total binding energy of the products is greater than the total binding energy of the reactants. This corresponds to the products being more stable than the reactants.$(i)$ $A + B \rightarrow C + \varepsilon$: Here,light nuclei $A$ and $B$ fuse to form a heavier nucleus $C$. Since $C$ has a higher binding energy per nucleon than $A$ and $B$,the total binding energy increases,and energy is released $(\varepsilon > 0)$.$(ii)$ $C \rightarrow A + B + \varepsilon$: This is the reverse of process $(i)$. Since the product nuclei are less stable,energy is absorbed $(\varepsilon $(iii)$ $D + E \rightarrow F + \varepsilon$: Here,$D$ and $E$ are relatively heavy nuclei. Fusing them to form $F$ (which is even heavier and less stable) would require energy input $(\varepsilon $(iv)$ $F \rightarrow D + E + \varepsilon$: This represents nuclear fission where a heavy,unstable nucleus $F$ splits into more stable,lighter nuclei $D$ and $E$. The total binding energy increases,so energy is released $(\varepsilon > 0)$.Therefore,processes $(i)$ and $(iv)$ result in energy release.

Similar Questions

The binding energy per nucleon for a deuteron and an $\alpha$-particle are $x_1$ and $x_2$ respectively. The energy $Q$ released in the following reaction is:
$_1H^2 + _1H^2 \rightarrow {_2}{He}^4 + Q$

The mass of a nucleus $_Z^AX$ is denoted by $M(A, Z)$. If $M_p$ and $M_n$ are the masses of a proton and a neutron respectively, the binding energy of this nucleus is given by:

If $M(A, Z)$,$M_p$,and $M_n$ denote the masses of the nucleus ${}_Z^AX$,proton,and neutron respectively in units of $u$ $(1u = 931.5 \text{ MeV}/c^2)$,and $BE$ represents its binding energy in $\text{MeV}$,then:

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