Find the ratio of the energy of an $X$-ray photon with a wavelength of $1 \mathring A$ to the energy of a visible light photon with a wavelength of $5000 \mathring A$.

If the cathode-anode potential difference in an $X$-ray tube is $10^5 V$,then the maximum energy of an $X$-ray photon can be:

The filament current in the electron gun of a Coolidge tube is increased while the potential difference used to accelerate the electrons is decreased. As a result, in the emitted radiation

$X$-rays of wavelength $\lambda$ are reflected from parallel planes of atoms in a crystal with spacing $d$ between two planes, as shown in the figure. If the two reflected beams interfere constructively, then the condition for maxima will be (where $n$ is the order of the interference fringe):

An $X$-ray tube with a copper target emits a $Cu$ $K_{\alpha}$ line of wavelength $1.50 \ \mathring{A}$. What should be the minimum voltage through which electrons are to be accelerated to produce this wavelength of $X$-rays? $(h = 6.63 \times 10^{-34} \ \text{J}\cdot\text{s}, c = 3 \times 10^8 \ \text{m/s})$

$X$-rays do not undergo diffraction because of their .....