$X$-rays do not undergo diffraction because of their .....

$(a)$ An $X$-ray tube produces a continuous spectrum of radiation with its short wavelength end at $0.45\,\mathring{A}$. What is the maximum energy of a photon in the radiation?
$(b)$ From your answer to $(a)$,guess what order of accelerating voltage (for electrons) is required in such a tube?

The wavelength of $L_{\alpha}$ line in $X$-ray spectrum of $_{78}Pt$ is $1.32 \ \mathring{A}$. The wavelength of $L_{\alpha}$ line in $X$-ray spectrum of another unknown element is $4.17 \ \mathring{A}$. If the screening constant for the $L_{\alpha}$ line is $7.4$,then the atomic number of the unknown element is:

If the attenuation coefficient of aluminum for soft $X$-rays is $1.73 \, cm^{-1}$,what percentage of $X$-rays will pass through an aluminum sheet of thickness $1.156 \, cm$?

When the potential difference applied to an $X$-ray tube is increased, the resulting emitted radiation shows:

The minimum wavelength of $X$-rays produced by electrons accelerated by a potential difference of $V$ volts is equal to: