If X-rays are produced by bombarding electron | vedclass

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(D) The energy of the incident electron is $E = 40 \ keV = 40 	imes 10^3 \ eV$.For $X$-rays,the minimum wavelength $\lambda_{\min}$ corresponds to th

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$0.31$

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(D) The energy of the incident electron is $E = 40 \ keV = 40 	imes 10^3 \ eV$.For $X$-rays,the minimum wavelength $\lambda_{\min}$ corresponds to the maximum energy of the emitted photon,which is equal to the kinetic energy of the incident electron.The relation is given by $E = \frac{hc}{\lambda_{\min}}$.Using $hc \approx 12400 \ eV \cdot \mathring{A}$,we have $\lambda_{\min} = \frac{12400 \ eV \cdot \mathring{A}}{40 	imes 10^3 \ eV}$.$\lambda_{\min} = \frac{12400}{40000} \ \mathring{A} = 0.31 \ \mathring{A}$.

If $X$-rays are produced by bombarding electrons with an energy of $40 \ keV$ on a target,what will be the minimum wavelength (in $\mathring{A}$) of the $X$-rays produced?

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