The energy of an electromagnetic radiation is | vedclass

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(A) The wavelength $\lambda$ is given by the formula $\lambda = \frac{hc}{E}$.Substituting the values: $h = 6.6 	imes 10^{-34} \, J \cdot s$,$c = 3 \

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$0.8 \, \mathring{A}$

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(A) The wavelength $\lambda$ is given by the formula $\lambda = \frac{hc}{E}$.Substituting the values: $h = 6.6 	imes 10^{-34} \, J \cdot s$,$c = 3 	imes 10^8 \, m/s$,and $E = 14.4 	imes 10^3 	imes 1.6 	imes 10^{-19} \, J$.$\lambda = \frac{6.6 	imes 10^{-34} 	imes 3 	imes 10^8}{14.4 	imes 10^3 	imes 1.6 	imes 10^{-19}}$$\lambda = \frac{19.8 	imes 10^{-26}}{23.04 	imes 10^{-16}}$$\lambda \approx 0.86 	imes 10^{-10} \, m = 0.86 \, \mathring{A}$.Since the wavelength is in the range of $0.01 \, \mathring{A}$ to $100 \, \mathring{A}$,this radiation belongs to the $X$-ray region of the electromagnetic spectrum.

The energy of an electromagnetic radiation is $14.4 \, KeV$. To which part of the electromagnetic spectrum does it belong?

Similar Questions

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