If the energy of a K-shell electron is -40000 | vedclass

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(C) The energy of the incident electron beam is given by $E = eV = 60000 \ eV$.The binding energy of the $K$-shell electron is $40000 \ eV$.Since the

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Continuous and all series of characteristic $X$-rays

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(C) The energy of the incident electron beam is given by $E = eV = 60000 \ eV$.The binding energy of the $K$-shell electron is $40000 \ eV$.Since the energy of the incident electrons $(60000 \ eV)$ is greater than the binding energy of the $K$-shell electrons $(40000 \ eV)$,the incident electrons have sufficient energy to knock out the $K$-shell electrons.When a $K$-shell electron is ejected,an electron from a higher energy level transitions to the $K$-shell,emitting characteristic $X$-rays of all series $(K, L, M, \dots)$.Additionally,the deceleration of incident electrons in the target produces continuous $X$-rays (Bremsstrahlung).Therefore,both continuous and all series of characteristic $X$-rays will be formed.

If the energy of a $K$-shell electron is $-40000 \ eV$ and a potential of $60000 \ V$ is applied to a Coolidge tube,which of the following $X$-rays will be formed?

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