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(A) $1$. In the first step,${}_{Z}^{A}X 	o {}_{Z+1}^{A}Y$,the atomic number $Z$ increases by $1$ while the mass number $A$ remains constant. This cor

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$\beta^-$,$\alpha$,$\gamma$

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(A) $1$. In the first step,${}_{Z}^{A}X 	o {}_{Z+1}^{A}Y$,the atomic number $Z$ increases by $1$ while the mass number $A$ remains constant. This corresponds to the emission of a $\beta^-$ particle.$2$. In the second step,${}_{Z+1}^{A}Y 	o {}_{Z-1}^{A-4}K$,the mass number $A$ decreases by $4$ and the atomic number $Z$ decreases by $2$. This corresponds to the emission of an $\alpha$ particle.$3$. In the third step,${}_{Z-1}^{A-4}K 	o {}_{Z-1}^{A-4}K$,there is no change in the mass number $A$ or the atomic number $Z$. This corresponds to the emission of a $\gamma$ ray (de-excitation of the nucleus).Therefore,the order of emission is $\beta^-$,$\alpha$,$\gamma$.

In the given nuclear decay process,identify the order in which radioactive radiations are emitted:
${}_{Z}^{A}X \to {}_{Z+1}^{A}Y \to {}_{Z-1}^{A-4}K \to {}_{Z-1}^{A-4}K$

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In the given nuclear decay process,identify the order in which radioactive radiations are emitted:${}_{Z}^{A}X \to {}_{Z+1}^{A}Y \to {}_{Z-1}^{A-4}K \to {}_{Z-1}^{A-4}K$