$A$ nucleus $_Z{X^A}$ emits $3 \alpha$-particles and $5 \beta$-particles. The ratio of total neutrons to protons in the final nucleus is:

  • A
    $\frac{A - Z - 12}{Z - 6}$
  • B
    $\frac{A - Z}{Z - 1}$
  • C
    $\frac{A - Z - 11}{Z - 6}$
  • D
    $\frac{A - Z - 11}{Z - 1}$

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