$A$ nuclear reactor provides power of $300 \, MW$. If $170 \, MeV$ of energy is released per fission of a $U^{235}$ nucleus, then the number of uranium atoms undergoing fission per hour is:

$U^{235}$ nuclear reactor generates energy at a rate of $3.70 \times 10^7 \text{ J/s}$. Each fission liberates $185 \text{ MeV}$ of useful energy. If the reactor has to operate for $144 \times 10^4 \text{ s}$, then the mass of the fuel needed is (Assume Avogadro's number $= 6 \times 10^{23} \text{ mol}^{-1}$, $1 \text{ eV} = 1.6 \times 10^{-19} \text{ J}$) (in $\text{ kg}$)

In a nuclear fission process,a high mass nuclide $(A \approx 236)$ with binding energy $7.6 \ MeV/\text{nucleon}$ dissociates into two middle mass nuclides $(A \approx 118)$,each having a binding energy of $8.6 \ MeV/\text{nucleon}$. The energy released in the process is $MeV$.

On bombarding $U^{235}$ by slow neutrons,$200 \text{ MeV}$ of energy is released. If the power output of an atomic reactor is $1.6 \text{ MW}$,then the rate of fission will be:

Solar energy is mainly caused due to

In any fission process,the ratio $\frac{\text{mass of fission products}}{\text{mass of parent nucleus}}$ is