A thin conducting spherical shell of radius R | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The total electric potential $V$ at point $P$ is the sum of the potential due to the charge $q$ on the shell and the potential due to the charge $

Vedclass · Accepted Answer

$\frac{2Q}{4\pi \epsilon_0 R} + \frac{q}{4\pi \epsilon_0 R}$

Vedclass · Answer

(C) The total electric potential $V$ at point $P$ is the sum of the potential due to the charge $q$ on the shell and the potential due to the charge $Q$ at the center.For a point inside a conducting shell,the potential due to the shell is constant and equal to the potential at its surface,which is $V_{shell} = \frac{1}{4\pi \epsilon_0} \frac{q}{R}$.The potential due to the point charge $Q$ at a distance $r = R/2$ is $V_{point} = \frac{1}{4\pi \epsilon_0} \frac{Q}{R/2} = \frac{1}{4\pi \epsilon_0} \frac{2Q}{R}$.Therefore,the total potential $V = V_{shell} + V_{point} = \frac{q}{4\pi \epsilon_0 R} + \frac{2Q}{4\pi \epsilon_0 R} = \frac{1}{4\pi \epsilon_0 R} (q + 2Q)$.

$A$ thin conducting spherical shell of radius $R$ has a charge $q$. Another charge $Q$ is placed at the center of the shell. The electrostatic potential at a point $P$ at a distance $R/2$ from the center of the shell is:

Similar Questions

Charges $+q$ and $-q$ are placed at points $A$ and $B$ respectively,which are a distance $2L$ apart. $C$ is the midpoint between $A$ and $B$. The work done in moving a charge $+Q$ along the semicircle $CRD$ is

Which one of the following is not a measurable quantity?

The electric potential inside a charged hollow conducting sphere is . . . . . . .

Draw a graph for the variation of electrostatic potential $V$ with distance $r$ from a point charge $Q$.

$A$ pellet carrying a charge of $0.5\, C$ is accelerated through a potential difference of $2,000\, V$. What is the kinetic energy attained by the pellet?

Vedclass Test Series

Exam Paper Generator

Online Exam Module