Two capacitors of values 0.6 mu F and 0.3 m | vedclass

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(A) In a series connection,the charge $Q$ on each capacitor is the same.The energy stored in a capacitor is given by $U = \frac{Q^2}{2C}$.Since $Q$ is

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$0.5$

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(A) In a series connection,the charge $Q$ on each capacitor is the same.The energy stored in a capacitor is given by $U = \frac{Q^2}{2C}$.Since $Q$ is constant for both capacitors in series,the energy stored is inversely proportional to the capacitance: $U \propto \frac{1}{C}$.Therefore,the ratio of energy stored in the first capacitor $(U_1)$ to the second capacitor $(U_2)$ is:$\frac{U_1}{U_2} = \frac{C_2}{C_1} = \frac{0.3 \ \mu F}{0.6 \ \mu F} = \frac{1}{2} = 0.5$.

Two capacitors of values $0.6 \ \mu F$ and $0.3 \ \mu F$ are connected in series with a $6 \ V$ source. Find the ratio of energy stored in each capacitor.

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