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(NONE) The circuit consists of two branches connected in parallel.
$1$. The top branch has two capacitors of capacitance $C$ in series. Their equival

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$C$

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(NONE) The circuit consists of two branches connected in parallel.
$1$. The top branch has two capacitors of capacitance $C$ in series. Their equivalent capacitance $C_1$ is given by $\frac{1}{C_1} = \frac{1}{C} + \frac{1}{C} = \frac{2}{C}$,so $C_1 = \frac{C}{2}$.
$2$. The bottom branch also has two capacitors of capacitance $C$ in series. Their equivalent capacitance $C_2$ is given by $\frac{1}{C_2} = \frac{1}{C} + \frac{1}{C} = \frac{2}{C}$,so $C_2 = \frac{C}{2}$.
$3$. These two branches are connected in parallel. Therefore,the total equivalent capacitance $C_{eq}$ is $C_{eq} = C_1 + C_2 = \frac{C}{2} + \frac{C}{2} = C$.

The equivalent capacitance of the combination shown is

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